Okay well todays assignment is to tell the steps on how to solve by substitution.
So i'll use an example to start of..
L1=2x+4y=8
L2=3x+y=13
(2x=4y=8)
step 1: then you take 4y and subtract it over to the other side
2x=8-4y
step 2: then you divide by 2 to get X by itself
x=(8-4y)/2
step:3 then you substitute it in to "L2"
3[(8-4y)/2]+y=13
step 4: then you multiply everything by 2.
6+16-8y+2y=26
step 5: collect the like terms now.
22-6y=26-22
-6y=4
step 6: to get y by its self, divide everything by -6
therefore, y= 4/-6 OR 2/-3
Now, you plot it in into one of the first solutions about
3(2/-3)+y=13
-2+y=13
y=13+2
y=15
THEREFORE: your plot would be [(2/-3),(15)]
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